S=-2.7t^2+30t+6.5

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Solution for S=-2.7t^2+30t+6.5 equation:



=-2.7S^2+30S+6.5
We move all terms to the left:
-(-2.7S^2+30S+6.5)=0
We get rid of parentheses
2.7S^2-30S-6.5=0
a = 2.7; b = -30; c = -6.5;
Δ = b2-4ac
Δ = -302-4·2.7·(-6.5)
Δ = 970.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$S_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$S_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$S_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-\sqrt{970.2}}{2*2.7}=\frac{30-\sqrt{970.2}}{5.4} $
$S_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+\sqrt{970.2}}{2*2.7}=\frac{30+\sqrt{970.2}}{5.4} $

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